prove that a3+b3+c3-3abc=1/2(a+b+c) (a-b)2+(b-c)2+(c-a)2

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Prove that a³ + b³ + c³ - 3abc = 1/2(a + b + c) {(a-b)² + (b-c)² + (c-a)²)}Prove that a³ + b³ + c³ - 3abc = 1/2(a + b + c) {(a-b)² + (b-c)² + (c-a)²)}
Prove : a^3+b^3+c^3-3abc = 1/2(a+b+c){(a-b)^2+(b-c)^2+(c-a)^2} | Rahul Sir | #mathshorts #shorts #Prove : a^3+b^3+c^3-3abc = 1/2(a+b+c){(a-b)^2+(b-c)^2+(c-a)^2} | Rahul Sir | #mathshorts #shorts #
Prove : `a^3+b^3+c^3-3abc = 1/2(a+b+c){(a-b)^2+(b-c)^2+(c-a)^2}`Prove : `a^3+b^3+c^3-3abc = 1/2(a+b+c){(a-b)^2+(b-c)^2+(c-a)^2}`
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99% WILL FAIL || A+A=2, A+B=3, A+B+C=6, A+B+C×4=❓🤔#shorts #bobby99% WILL FAIL || A+A=2, A+B=3, A+B+C=6, A+B+C×4=❓🤔#shorts #bobby
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