In the figure, D is the point on the base BC of the triangle ABC such that ADC = BAC. Prove that CA…

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D is a point on the side BC of a triangle ABC such that ∠ADC = ∠BAC | Exercise 6.3 class 10 Q13D is a point on the side BC of a triangle ABC such that ∠ADC = ∠BAC | Exercise 6.3 class 10 Q13
In the given figure, D is a point on the side BC of △ABC such that ∠ADC=∠BAC. Show that CA² = CD. CBIn the given figure, D is a point on the side BC of △ABC such that ∠ADC=∠BAC. Show that CA² = CD. CB
In the given figure, D is a point on the side BC of △ABC such that ∠ADC= ∠BAC. Show that CA²= CD.CB.In the given figure, D is a point on the side BC of △ABC such that ∠ADC= ∠BAC. Show that CA²= CD.CB.
(a) In the given figure, D is a point on the side BC of △ABC such that ∠ADC = ∠BAC. Show that CA²(a) In the given figure, D is a point on the side BC of △ABC such that ∠ADC = ∠BAC. Show that CA²
D is a point on the side BC of a triangle ABC such that ∠ADC=∠BAC. Show that CA²=CB.CD.D is a point on the side BC of a triangle ABC such that ∠ADC=∠BAC. Show that CA²=CB.CD.
D is a point on the side BC of a triangle ABC such that ∠ADC = ∠ BAC. Show that CA2 = CB.CDD is a point on the side BC of a triangle ABC such that ∠ADC = ∠ BAC. Show that CA2 = CB.CD
Ques 13.D is a point on the side BC of a triangle ABC, such that ∠ADC = ∠BAC. Show that CA² = CB.CD.Ques 13.D is a point on the side BC of a triangle ABC, such that ∠ADC = ∠BAC. Show that CA² = CB.CD.
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