In the given figure, D is a point on the side BC of △ABC such that ∠ADC=∠BAC. Show that CA² = CD. CB

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D is a point on the side BC of a triangle ABC such that ∠ADC = ∠BAC | Exercise 6.3 class 10 Q13D is a point on the side BC of a triangle ABC such that ∠ADC = ∠BAC | Exercise 6.3 class 10 Q13
D is a point on the side BC of a triangle ABC such that ADC = BAC. Show that CA^2 = CB.CD.D is a point on the side BC of a triangle ABC such that ADC = BAC. Show that CA^2 = CB.CD.
In the given figure, D is a point on the side BC of △ABC such that ∠ADC= ∠BAC. Show that CA²= CD.CB.In the given figure, D is a point on the side BC of △ABC such that ∠ADC= ∠BAC. Show that CA²= CD.CB.
🚜 In🔺ABC 📐 ADC = 📐 BAC prove that CA/CD = CB/CA or CA² = CB x CD #techno_mathics🚜 In🔺ABC 📐 ADC = 📐 BAC prove that CA/CD = CB/CA or CA² = CB x CD #techno_mathics
D is a point on the side BC of a triangle ABC such that ∠ADC=∠BAC. Show that CA²=CB.CD.D is a point on the side BC of a triangle ABC such that ∠ADC=∠BAC. Show that CA²=CB.CD.
D is a point on the side BC of triangleABC such that angleADC= angleBAC, prove that CA^(2)=CBxxC...D is a point on the side BC of triangleABC such that angleADC= angleBAC, prove that CA^(2)=CBxxC...
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D is a point on the side BC of a triangle ABC such that angle ADC=angle BAC. Show that CA²=CB.CD.D is a point on the side BC of a triangle ABC such that angle ADC=angle BAC. Show that CA²=CB.CD.