The least value of the function f(x)= x^3-18x^2+96x interval [0,9]|RD Sharma|12|Part 1|2023|CBSE|MCQ

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Prove that, maximum and minimum values of the function `x^3 -18x^2 +96x` in the interval `(0,Prove that, maximum and minimum values of the function `x^3 -18x^2 +96x` in the interval `(0,
Prove that maximum and minimum values of the function `x^3-18x^2 + 96x` in the interval `(0, 9Prove that maximum and minimum values of the function `x^3-18x^2 + 96x` in the interval `(0, 9
The least value of the function `f(x)=x^3-18 x^2+96 x` in the interval `[0,9]` is 126 (b) 135 (c...The least value of the function `f(x)=x^3-18 x^2+96 x` in the interval `[0,9]` is 126 (b) 135 (c...
Prove that, maximum and minimum values of the function `x^3 -18x^2 +96x` in the interval `(0,Prove that, maximum and minimum values of the function `x^3 -18x^2 +96x` in the interval `(0,
GIVEN THAT THE SMALLEST VALUE OF POLYNOMIAL IS F(X) = X^3-18X^2+96X IN [0,9] ISGIVEN THAT THE SMALLEST VALUE OF POLYNOMIAL IS F(X) = X^3-18X^2+96X IN [0,9] IS
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