In ABC, if AD ⊥ BC and AD² = BD × DC , then prove that ∠BAC = 90°. #2025boardexamsolutions

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X Maths Standard 2025 In Δ ABC, if AD ⊥ BC and AD² = BD x DC, then prove that ∠ BAC = 90°.X Maths Standard 2025 In Δ ABC, if AD ⊥ BC and AD² = BD x DC, then prove that ∠ BAC = 90°.
In △ABC, if AD ⊥ BC and AD²=BD x DC , then prove that ∠BAC=90° #cbse #cbse10th #mathsIn △ABC, if AD ⊥ BC and AD²=BD x DC , then prove that ∠BAC=90° #cbse #cbse10th #maths
33 b. In ABC, if AD perpendicular BC and AD2 = BD* DC, , then prove that BAC = 9033 b. In ABC, if AD perpendicular BC and AD2 = BD* DC, , then prove that BAC = 90
In triangle ABC ,if AD perpendicular to BC and AD² = BD × DC then prove that angle BAC = 90⁰ #cbseIn triangle ABC ,if AD perpendicular to BC and AD² = BD × DC then prove that angle BAC = 90⁰ #cbse
Q35 In ∆ ABC , if AD is perpendicular to BC and AD2=BD*DC then prove that angle BAC =90°Q35 In ∆ ABC , if AD is perpendicular to BC and AD2=BD*DC then prove that angle BAC =90°
In triangle ABC, if AD is perpendicular to BC and AD² = BD × DC, then prove that angle BAC = 90°In triangle ABC, if AD is perpendicular to BC and AD² = BD × DC, then prove that angle BAC = 90°
Class 10 CBSE 2024 exam question || In ∆ABC, if AD ⊥ BC and AD²=BD×DC, then prove that ∠ BAC=90°Class 10 CBSE 2024 exam question || In ∆ABC, if AD ⊥ BC and AD²=BD×DC, then prove that ∠ BAC=90°
Q33(b) In ABC, if AD BC and AD2 = BD*DC, then prove that Angle BAC = 90°.Q33(b) In ABC, if AD BC and AD2 = BD*DC, then prove that Angle BAC = 90°.