log5(x+3) = 1 - log5(x-1),, solve for x

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log[5,x+3] = 1 - log[5, x-1]log[5,x+3] = 1 - log[5, x-1]
log5(x+3) - log5x = 1, solve for xlog5(x+3) - log5x = 1, solve for x
Solve logarithmic equation with different bases | log_2(x) + log_5(x)= 4.Solve logarithmic equation with different bases | log_2(x) + log_5(x)= 4.
Solving LOGARITHM Equation: log(5) (x + 1) - log(5) (x - 1) = 2Solving LOGARITHM Equation: log(5) (x + 1) - log(5) (x - 1) = 2
log5(2x+3) = log5(3), solve for xlog5(2x+3) = log5(3), solve for x
Solving Log EquationSolving Log Equation
Logarithmic Form to Exponential Form 📚 #Shorts #algebra #math #maths #mathematics #educationLogarithmic Form to Exponential Form 📚 #Shorts #algebra #math #maths #mathematics #education
Logarithmic Form to Exponential Form 🤯 #Shorts #algebra #math #maths #mathematics #education #learnLogarithmic Form to Exponential Form 🤯 #Shorts #algebra #math #maths #mathematics #education #learn