In a triangle PQR, N is a point on PR such that QN ⊥ PR if PN X NR= QN² prove PQR=90 I class 10

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In a triangle ∆PQR, N is a point on PR such that QN ⊥ PR if PN X NR= QN² prove that ∠PQR = 90°In a triangle ∆PQR, N is a point on PR such that QN ⊥ PR if PN X NR= QN² prove that ∠PQR = 90°
In triangle PQR, N is a point on PR such that QN ⊥ PR if PN X NR= QN² prove angle PQR=90 I class 10In triangle PQR, N is a point on PR such that QN ⊥ PR if PN X NR= QN² prove angle PQR=90 I class 10
In a triangle PQR, N is a point on PR such that QN⊥PR. If PN . NR=QN^2, prove that ∠PQR=90^∘. (W)In a triangle PQR, N is a point on PR such that QN⊥PR. If PN . NR=QN^2, prove that ∠PQR=90^∘. (W)
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In a triangle PQR, N is a point on PR such that QN is perpendicular to PR. If PN.NR = QN^2, thenIn a triangle PQR, N is a point on PR such that QN is perpendicular to PR. If PN.NR = QN^2, then
In a Delta PQR, N is a point on PR, such that QNbotPR. If PNcdotNR=QN^(2), then prove that angle...In a Delta PQR, N is a point on PR, such that QNbotPR. If PNcdotNR=QN^(2), then prove that angle...
In ∆PQR, N is point on PR, such that QN perpendicular PR. If PN×NR=QN^2, Prove that angle PQR=90° |In ∆PQR, N is point on PR, such that QN perpendicular PR. If PN×NR=QN^2, Prove that angle PQR=90° |
In triangle PQR N is a point on PRIn triangle PQR N is a point on PR