If `alphain(0,pi/2)` then `sqrt(x^2+x)+(tanalpha)^2/(sqrt(x^2+x))` is always greater than or eq...

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If \[\alpha \; \in \;(0\;,\;\pi /2)\], then \[\sqrt {{x^2} + x} \; + \;\frac{{{{\tan }^2}\alpha }}{If \[\alpha \; \in \;(0\;,\;\pi /2)\], then \[\sqrt {{x^2} + x} \; + \;\frac{{{{\tan }^2}\alpha }}{
If \( \alpha \in\left(0, \frac{\pi}{2}\right) \) then \( \sqrt{x^{2}+x}+\frac{\tan ^{2} \alpha}{...If \( \alpha \in\left(0, \frac{\pi}{2}\right) \) then \( \sqrt{x^{2}+x}+\frac{\tan ^{2} \alpha}{...
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