Ratio of Zeroes of the Polynomial = 3:4, Prove 12a^2 = 49b! Class 10th Maths CBSE PYQ Breakdown

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Q21 If the zeroes of the polynomial x2 + ax + b are in the ratio 3 : 4, then prove that 12a2 = 49b.Q21 If the zeroes of the polynomial x2 + ax + b are in the ratio 3 : 4, then prove that 12a2 = 49b.
If the zeroes of the polynomial x² + ax + b are in the ratio 3:4, then prove that 12a²=49 bIf the zeroes of the polynomial x² + ax + b are in the ratio 3:4, then prove that 12a²=49 b
If the zeroes of the polynomial x2 + ax + b are in the ratio 3 : 4, then prove that 12a2 = 49b.If the zeroes of the polynomial x2 + ax + b are in the ratio 3 : 4, then prove that 12a2 = 49b.
IIf the zeroes of polynomial x²+ax+b are in the ratio 3:4 then prove that 12a²=49bIIf the zeroes of polynomial x²+ax+b are in the ratio 3:4 then prove that 12a²=49b
If the zeroes of the polynomial x²+ax+b are in the ratio 3:4, then prove that 12a²=49b. @classdemicsIf the zeroes of the polynomial x²+ax+b are in the ratio 3:4, then prove that 12a²=49b. @classdemics
If the roots of ax^2+bx+c=0 be in the ratio 3:4 prove that, 12b^2=49acIf the roots of ax^2+bx+c=0 be in the ratio 3:4 prove that, 12b^2=49ac
If the zeros of the polynomial x2+ax+b are in the ratio 3:4 , then prove that 12a2 =49b.#class10If the zeros of the polynomial x2+ax+b are in the ratio 3:4 , then prove that 12a2 =49b.#class10
Secret of Fast Calculation 🔥|| Shobhit Nirwan #class10 #shorts #cbse #motivationSecret of Fast Calculation 🔥|| Shobhit Nirwan #class10 #shorts #cbse #motivation