💥 If the Zeroes of x² + ax + b are in 3:4, Prove that 12a² = 49b | Sumit Sir | Deserve Point Academy

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Q21 If the zeroes of the polynomial x2 + ax + b are in the ratio 3 : 4, then prove that 12a2 = 49b.Q21 If the zeroes of the polynomial x2 + ax + b are in the ratio 3 : 4, then prove that 12a2 = 49b.
If the zeroes of the polynomial x²+ax+b are in the ratio 3:4, then prove that 12a²=49b. @classdemicsIf the zeroes of the polynomial x²+ax+b are in the ratio 3:4, then prove that 12a²=49b. @classdemics
If the zeros of the polynomial x2+ax+b are in the ratio 3:4 , then prove that 12a2 =49b.#class10If the zeros of the polynomial x2+ax+b are in the ratio 3:4 , then prove that 12a2 =49b.#class10
IIf the zeroes of polynomial x²+ax+b are in the ratio 3:4 then prove that 12a²=49bIIf the zeroes of polynomial x²+ax+b are in the ratio 3:4 then prove that 12a²=49b
If the zeroes of the polynomial x² + ax + b are in the ratio 3:4, then prove that 12a²=49 bIf the zeroes of the polynomial x² + ax + b are in the ratio 3:4, then prove that 12a²=49 b
If the zeroes of the polynomial x2 + ax + b are in the ratio 3 : 4, then prove that 12a2 = 49b.If the zeroes of the polynomial x2 + ax + b are in the ratio 3 : 4, then prove that 12a2 = 49b.
If the roots of ax^2+bx+c=0 be in the ratio 3:4 prove that, 12b^2=49acIf the roots of ax^2+bx+c=0 be in the ratio 3:4 prove that, 12b^2=49ac
Ch2 - Polynomial Short Trick | Class 10 | 🔥 Find Sign of a b c from GraphCh2 - Polynomial Short Trick | Class 10 | 🔥 Find Sign of a b c from Graph