Use MI to prove 1³+2³+....n³= n²(n+1)²/4 Part1

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prove by the principle of mathematical induction that 1³+2³+3³+...+n³=(n²(n+1)²)/4prove by the principle of mathematical induction that 1³+2³+3³+...+n³=(n²(n+1)²)/4
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Prove by Induction sum of first n Cubes ,1^3+2^3+3^3+... +n^3=n^2(n+1)^2÷4Prove by Induction sum of first n Cubes ,1^3+2^3+3^3+... +n^3=n^2(n+1)^2÷4