Prove the identity: √(secA-1)/(secA+1) + √(secA+1)/(secA-1) = 2 cosec A

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Root{(secA-1) /(secA+1)} + Root{(secA+1) /(secA-1) = 2cosecA under root seca-1/seca+1Root{(secA-1) /(secA+1)} + Root{(secA+1) /(secA-1) = 2cosecA under root seca-1/seca+1
Prove that √(secA-1)/(secA+1) +√(secA+1)/(secA-1) =2 cosecAProve that √(secA-1)/(secA+1) +√(secA+1)/(secA-1) =2 cosecA
Root((SecA-1)/(SecA+1))+root((SecA+1)/(SecA-1))=2.CosecA Trigonometry 10th MathsRoot((SecA-1)/(SecA+1))+root((SecA+1)/(SecA-1))=2.CosecA Trigonometry 10th Maths
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Q83 | Prove that √((sec⁡θ-1)/(sec⁡θ+1))+√((sec⁡θ+1)/(sec⁡θ-1))=2 cosec⁡θ | under root sec theta - 1Q83 | Prove that √((sec⁡θ-1)/(sec⁡θ+1))+√((sec⁡θ+1)/(sec⁡θ-1))=2 cosec⁡θ | under root sec theta - 1
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prove that root(cosecA - 1)/(cosecA + 1)+root(cosecA + 1)/(cosecA - 1)= 2 sec A trigono class 10prove that root(cosecA - 1)/(cosecA + 1)+root(cosecA + 1)/(cosecA - 1)= 2 sec A trigono class 10