D is a point on the side BC of a ∆ ABC such that AD bisects ∠BAC. Then (A) BD = CD (B

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D is a point on the side BC of a triangle ABC such that ∠ADC = ∠BAC | Exercise 6.3 class 10 Q13D is a point on the side BC of a triangle ABC such that ∠ADC = ∠BAC | Exercise 6.3 class 10 Q13
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D is a point on the side BC of triangle ABC such that angle ACD = angle BAC show that AC^2= BC.DC .D is a point on the side BC of triangle ABC such that angle ACD = angle BAC show that AC^2= BC.DC .
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D is a point on the side BC of a triangle ABC such that ∠ADC=∠BAC. Show that CA²=CB.CD.D is a point on the side BC of a triangle ABC such that ∠ADC=∠BAC. Show that CA²=CB.CD.
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