If gcd(a,b)=1 and c|a, then gcd(b,c)=1

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If gcd(a,b)=1 and c|(a+b), then gcd(a,c)=gcd(b,c)=1If gcd(a,b)=1 and c|(a+b), then gcd(a,c)=gcd(b,c)=1
If gcd(a,b)=1, then gcd(ac,b)=gcd(c,b)If gcd(a,b)=1, then gcd(ac,b)=gcd(c,b)
If gcd(a,b)=1 and gcd(a,c)=1, then gcd(a,bc)=1.If gcd(a,b)=1 and gcd(a,c)=1, then gcd(a,bc)=1.
If a|b+c and gcd(b,c)=1, then gcd(a,b)=1=gcd(a,c).If a|b+c and gcd(b,c)=1, then gcd(a,b)=1=gcd(a,c).
If gcd(a,b)=1, d|ac, and d|bc, then d|c.If gcd(a,b)=1, d|ac, and d|bc, then d|c.
Show that if gcd(a,b)=1 and gcd(a,c)=1, then gcd(a, bc)=1 [NT-Ch.2-S2.5] - Part 9Show that if gcd(a,b)=1 and gcd(a,c)=1, then gcd(a, bc)=1 [NT-Ch.2-S2.5] - Part 9
If c|a and c|b, then c|gcd(a, b)If c|a and c|b, then c|gcd(a, b)
Prove gcd(a,bc) = 1 if and only if gcd(a,b) = 1 and gcd(a,c) = 1 (ILIEKMATHPHYSICS)Prove gcd(a,bc) = 1 if and only if gcd(a,b) = 1 and gcd(a,c) = 1 (ILIEKMATHPHYSICS)