JEE 2025 Equation x²+4x-n=0, where n(20, 100).number of n given equation has integral root #jeemains

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JEE Mains 2025 Quadratic Trick | Find n for Integral Roots of x² + 4x − n = 0 🔥JEE Mains 2025 Quadratic Trick | Find n for Integral Roots of x² + 4x − n = 0 🔥
Consider the equation x² + 4x + n = 0 where n ∈ [20 100] is a natural number Then the number of allConsider the equation x² + 4x + n = 0 where n ∈ [20 100] is a natural number Then the number of all
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Consider the equation x^2+4x-n=0, where n∈[20,100] is a natural number. Then the number #jeemainConsider the equation x^2+4x-n=0, where n∈[20,100] is a natural number. Then the number #jeemain
Consider the equation x² + 4x − n = 0 where n ∈ [20, 100] is a natural number. Then the number of Consider the equation x² + 4x − n = 0 where n ∈ [20, 100] is a natural number. Then the number of
Consider the equatin x^2+4x-n=0, where n∈[20,100] is a natural number. Then the number of all distinConsider the equatin x^2+4x-n=0, where n∈[20,100] is a natural number. Then the number of all distin
If the root of x²-4x-n=0 are integral , n€ N and n€[20,100] then [ 4th April 2025 (JEE main)]If the root of x²-4x-n=0 are integral , n€ N and n€[20,100] then [ 4th April 2025 (JEE main)]