If α + iβ and γ + iδ are roots of the equation: x² - (3 - 2i)x - (2i - 2) = 0 where: i = √(-1) | JEE

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If 𝛼+i𝛽 and 𝛾+i𝛿 are the roots of x^2−(3−2i)x−(2i−2)=0,i=√(−1), then 𝛼𝛾+𝛽𝛿 is #jee2026 #maths #jeeIf 𝛼+i𝛽 and 𝛾+i𝛿 are the roots of x^2−(3−2i)x−(2i−2)=0,i=√(−1), then 𝛼𝛾+𝛽𝛿 is #jee2026 #maths #jee
Q) If 𝛼+𝑖𝛽 and 𝛾+𝑖𝛿 are the roots of 𝑥^2−(3−2𝑖)𝑥−(2𝑖−2) =0, then 𝛼𝑦+𝛽𝛿 is #jee2026Q) If 𝛼+𝑖𝛽 and 𝛾+𝑖𝛿 are the roots of 𝑥^2−(3−2𝑖)𝑥−(2𝑖−2) =0, then 𝛼𝑦+𝛽𝛿 is #jee2026
JEE Main-PYQ-2025 - If +iβ and +iδ are the roots of x2-(3-2i)x-(2i-2)=0,i=-1, then αγ+βδ is equal toJEE Main-PYQ-2025 - If +iβ and +iδ are the roots of x2-(3-2i)x-(2i-2)=0,i=-1, then αγ+βδ is equal to
If α + iβ and γ + iδ are the roots of X² - (3 - 2i)x - (2i-2 ) = 0 then αγ + βδ is equal to:If α + iβ and γ + iδ are the roots of X² - (3 - 2i)x - (2i-2 ) = 0 then αγ + βδ is equal to:
IIT JEE MAINS -COMPLEX NO If α + iβ and γ+iδ are the roots of x²- (3-2i) x- (2i-2)=0 then αγ+βδ isIIT JEE MAINS -COMPLEX NO If α + iβ and γ+iδ are the roots of x²- (3-2i) x- (2i-2)=0 then αγ+βδ is
Q) If 𝛼+𝑖𝛽 and 𝛾+𝑖𝛿 are the roots of 𝑥^2−(3−2𝑖)𝑥−(2𝑖−2) =0, then 𝛼𝑦+𝛽𝛿 is #jee2026Q) If 𝛼+𝑖𝛽 and 𝛾+𝑖𝛿 are the roots of 𝑥^2−(3−2𝑖)𝑥−(2𝑖−2) =0, then 𝛼𝑦+𝛽𝛿 is #jee2026
If α+iβ and γ+iδ are the roots of x^2-(3-2i)x-(2i-2) = 0, i=√(-1) , then αγ+βδ is equal to #iitIf α+iβ and γ+iδ are the roots of x^2-(3-2i)x-(2i-2) = 0, i=√(-1) , then αγ+βδ is equal to #iit
🧠 JEE Mains PYQ | Number of Real Roots 🚀#jee #jeemains #iitjee #maths🧠 JEE Mains PYQ | Number of Real Roots 🚀#jee #jeemains #iitjee #maths