Q) If 𝜃∈[−7𝜋/6,4𝜋/3], then the number of solutions of √3 cosec^2 𝜃−2(√3−1)cosec𝜃−4=0,

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Q) If 𝜃∈[−7𝜋/6,4𝜋/3], then the number of solutions of√3 cosec^2 𝜃−2(√3−1)cosec𝜃 −4=0, is

If θ ∈ [-7π/6,4π/3], then the number of solutions of √3 cosec^2 θ-2(√3-1)cosecθ-4=0, #jeemain #pyq

If θ∈[-7π/6,4π/3], then the number of solutions of √3 cosec^2 θ-2(√3-1)cosecθ-4=0, is equal to

Q) θ∈[-7π/3,4π/3],then the number of solutions √3cosec^θ - 2(√3 -1)cosecθ -4 = 0

JEE ADVANCE : For θ ∈ ( 0,π/2) , the solution(s) Σ_(m=1)^(6) cosec(θ+(m-1)π/4)cosec(θ+mπ/4) = 4√2

If tan θ = 1/√7, show that (cosec^2 θ - sec^2 θ)/(cosec^2 θ + sec^2 θ) = 4/3 | Trigonometry

A Tricky Maths Exam Question | Solve for k

If sin θ = 3/4,show that√((cosec^2 θ-cot^2 θ)/(sec^2 θ))=√7/3. Class-10 Trigonometry