if A+B+C=180 Prove that cotAcotB+cotBcotC+cotCcotA=1

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If `A+B+C=180^@` then the value of `(cotB+cotC)(cotC+cotA)(cotA+cotB)` will beIf `A+B+C=180^@` then the value of `(cotB+cotC)(cotC+cotA)(cotA+cotB)` will be
Prove that:- cot(A+B+C)=(cotAcotBcotC-cotA-cotB-cotC)/(cotAcotB+cotBcotC+cotAcotC-1)Prove that:- cot(A+B+C)=(cotAcotBcotC-cotA-cotB-cotC)/(cotAcotB+cotBcotC+cotAcotC-1)
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