In a triangle ABC, BO and CO are the angle Bisectors of ∠B and ∠C, prove that ∠O = 90°+ 1/2 ∠A.

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In a triangle ABC, BO and CO are the angle Bisectors of angle B and angle C, prove ∠O = 90°+ 1/2 ∠AIn a triangle ABC, BO and CO are the angle Bisectors of angle B and angle C, prove ∠O = 90°+ 1/2 ∠A
In a ∆ABC,the bisectors of B and C intersect each other point o.prove BOC =90° +1/2AIn a ∆ABC,the bisectors of B and C intersect each other point o.prove BOC =90° +1/2A
If BO and CO are angle bisectors of ∠B and ∠C respectively, then ∠BOC = 90° + ∠A/2. Solve With SunnyIf BO and CO are angle bisectors of ∠B and ∠C respectively, then ∠BOC = 90° + ∠A/2. Solve With Sunny
Example8 -Ncert-the sides AB and AC of ∆ABC are produced to points E and D respectively.-Class9Example8 -Ncert-the sides AB and AC of ∆ABC are produced to points E and D respectively.-Class9
Prove that ∠BOC = 90° - (1/2)∠A |Bisectors of ∠B and ∠C of △ABC intersect each other at the point OProve that ∠BOC = 90° - (1/2)∠A |Bisectors of ∠B and ∠C of △ABC intersect each other at the point O
In Fig. the sides AB and AC of ∆ABC are produced to points E and D respectively. If bisectors BOIn Fig. the sides AB and AC of ∆ABC are produced to points E and D respectively. If bisectors BO
How to draw bisector of angle in triangle#shorts#yt trendingshorts#viralshorts#RB knowledge exploreHow to draw bisector of angle in triangle#shorts#yt trendingshorts#viralshorts#RB knowledge explore
DAV | CLASS-9 | MATHS | LINES AND ANGLES | Prove Angle BOC= 90°- Angle A/2 | By OM GuptaDAV | CLASS-9 | MATHS | LINES AND ANGLES | Prove Angle BOC= 90°- Angle A/2 | By OM Gupta