In ΔABC,(b-c)cot A/2+(c-a)cot B/2+(a-b)cot C/2 is equal to

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In any triangle `A B C ,` prove that: `(b-c)cot A/2+(c-a)cot B/2+(a-b)cot C/2` =0In any triangle `A B C ,` prove that: `(b-c)cot A/2+(c-a)cot B/2+(a-b)cot C/2` =0
In a `DeltaABC`, prove that `(b-c)cot\"\"A/2+(c-a)cot\"\"B/2+(a-b)cot\"\"C/2=0`In a `DeltaABC`, prove that `(b-c)cot\"\"A/2+(c-a)cot\"\"B/2+(a-b)cot\"\"C/2=0`
Show that in a triangle ABC, cot(A/2) + cot(B/2) + cot(C/2) = cot(A/2)*cot(B/2)*cot(C/2)Show that in a triangle ABC, cot(A/2) + cot(B/2) + cot(C/2) = cot(A/2)*cot(B/2)*cot(C/2)
In any `Delta ABC` , `cot(A/2),cot(B/2),cot(C/2)` are in `A.P.`, thenIn any `Delta ABC` , `cot(A/2),cot(B/2),cot(C/2)` are in `A.P.`, then
In a `"DeltaA B C` prove that `tan(("A"+"B")/2)=cot("C"/2)`In a `"DeltaA B C` prove that `tan(("A"+"B")/2)=cot("C"/2)`
Prove that tan (B+C/2)=cotA/2 exercise 7.2 q.n. 17Prove that tan (B+C/2)=cotA/2 exercise 7.2 q.n. 17
In a triangle ABC, `a-2b +c=0`.The value of `cot(A/2)cot(C/2)` isIn a triangle ABC, `a-2b +c=0`.The value of `cot(A/2)cot(C/2)` is
In `DeltaABC`, if `cot(A/2):cot(B/2):cot(C/2)=3:7:9,` then `a:b:c=`In `DeltaABC`, if `cot(A/2):cot(B/2):cot(C/2)=3:7:9,` then `a:b:c=`