If `a = 1 + "log"_(x) yz, b = 1 + "log"_(y) zx, c =1 + "log"_(z) xy,` then ab+bc+ca =

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If a = 1 + log_(x) yz, b = 1 + log_(y) zx, c =1 + log_(z) xy, then ab+bc+ca = | 12 | SEQUENCES A...If a = 1 + log_(x) yz, b = 1 + log_(y) zx, c =1 + log_(z) xy, then ab+bc+ca = | 12 | SEQUENCES A...
If `x=1+log_(a) bc, y=1+log_(b) ca, z=1+log_(c) ab`, then `(xyz)/(xy+yz+zx)` is equal toIf `x=1+log_(a) bc, y=1+log_(b) ca, z=1+log_(c) ab`, then `(xyz)/(xy+yz+zx)` is equal to
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Given x = 1+log_a⁡bc; y = 1+log_b⁡ca; z = 1+log_c⁡ab, show that xy + yz + zx = xyz. LOGARITHMSGiven x = 1+log_a⁡bc; y = 1+log_b⁡ca; z = 1+log_c⁡ab, show that xy + yz + zx = xyz. LOGARITHMS
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