IIT JEE PERMUTATIONS AND COMBINATIONS If `10! =2^p .3^q .5^r .7^s`, then `(A)` `2q = p` `(B)` ...

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If 10! =2^p .3^q .5^r .7^s, then\n(A) 2q = p \n(B) pqrs = 64 \n(C) number of divisors of 10! is ...If 10! =2^p .3^q .5^r .7^s, then\n(A) 2q = p \n(B) pqrs = 64 \n(C) number of divisors of 10! is ...
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