In a \( \triangle A B C \), if \( A=30^{\circ}, b=2, c=\sqrt{3}+1 \), then \( \frac{C-B}{2}= \) ...

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Solve triangle ABC when A = 30 degrees, a = 2, b = 2 sqrt(3).Solve triangle ABC when A = 30 degrees, a = 2, b = 2 sqrt(3).
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