JEE Main 2024:If a = lim(x→0) √1+√1+x⁴ - √2 / x⁴ and b = lim(x→0) sin²x/√2-√1+cosx, the value of ab³

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Q) If a=lim(x→0) (√(1+√(1+x^4 )) −√2)/x^4 and 𝑏=lim(𝑥→0) (sin^2 𝑥)/(√2−√(1+cos𝑥)), then the vaQ) If a=lim(x→0) (√(1+√(1+x^4 )) −√2)/x^4 and 𝑏=lim(𝑥→0) (sin^2 𝑥)/(√2−√(1+cos𝑥)), then the va
Ifa=limit x tends to0{root(1+ root(1+x^4)-root 2}\x^4&b=limit x tends to0(sin^2x)/root2-root(1+cosx)Ifa=limit x tends to0{root(1+ root(1+x^4)-root 2}\x^4&b=limit x tends to0(sin^2x)/root2-root(1+cosx)
lim (x → 0) sin²x / ( √2 − √(1 + cos x) ) equals:lim (x → 0) sin²x / ( √2 − √(1 + cos x) ) equals:
For 𝛼,𝛽,𝛾∈𝑅, if lim(𝑥→0) (𝑥^2 sin𝛼𝑥(𝛾−1)𝑒^(𝑥^2 ))/(sin2𝑥−𝛽𝑥)=3, then 𝛽+𝛾−𝛼 is #jee #maths #jeeFor 𝛼,𝛽,𝛾∈𝑅, if lim(𝑥→0) (𝑥^2 sin𝛼𝑥(𝛾−1)𝑒^(𝑥^2 ))/(sin2𝑥−𝛽𝑥)=3, then 𝛽+𝛾−𝛼 is #jee #maths #jee
Q) For 𝛼,𝛽,𝛾∈𝑅, if lim(𝑥→0) (𝑥^2 sin𝛼𝑥(𝛾−1)𝑒^(𝑥^2 ))/(sin2𝑥−𝛽𝑥)=3, then 𝛽+𝛾−𝛼 is #jee #maths #jeeQ) For 𝛼,𝛽,𝛾∈𝑅, if lim(𝑥→0) (𝑥^2 sin𝛼𝑥(𝛾−1)𝑒^(𝑥^2 ))/(sin2𝑥−𝛽𝑥)=3, then 𝛽+𝛾−𝛼 is #jee #maths #jee
\( a=\lim _{x \rightarrow 0} \frac{\sqrt{1 \sqrt{1 x^{4}}}-\sqrt{2}}{x^{4}} \) and \( b=\lim _{x....\( a=\lim _{x \rightarrow 0} \frac{\sqrt{1 \sqrt{1 x^{4}}}-\sqrt{2}}{x^{4}} \) and \( b=\lim _{x....
lim x→0 sin²(x)/(√2 - √(1 + cos(x))). JEE-Main India, 8 Apr 2019, Morning Shift, Question 72.lim x→0 sin²(x)/(√2 - √(1 + cos(x))). JEE-Main India, 8 Apr 2019, Morning Shift, Question 72.
Tamasha Dekho 😂 IITian Rocks Relatives Shock 😂😂😂 #JEEShorts #JEE #ShortsTamasha Dekho 😂 IITian Rocks Relatives Shock 😂😂😂 #JEEShorts #JEE #Shorts