Q24(a) In the given figure, D is a point on the side BC of ABC such that ADC = BAC. Show that CA2

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D is a point on the side BC of triangleABC such that angleADC= angleBAC, prove that CA^(2)=CBxxC...D is a point on the side BC of triangleABC such that angleADC= angleBAC, prove that CA^(2)=CBxxC...
D is a point on the side BC of a triangle ABC such that ∠ADC=∠BAC. Show that CA²=CB.CD.D is a point on the side BC of a triangle ABC such that ∠ADC=∠BAC. Show that CA²=CB.CD.
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