If `a,b,c` are in A.P then the value of `|[x+1, x+2, x+a] , [x+2, x+3, x+b] , [x+3, x+4, x+c]|

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If a,b,c are in AP show that `|[x+1,x+2,x+a],[x+2,x+3,x+b],[x+3,x+4,x+c]|=0`If a,b,c are in AP show that `|[x+1,x+2,x+a],[x+2,x+3,x+b],[x+3,x+4,x+c]|=0`
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