What is the formula for 1^4+2^4+3^4+...+r^4+...+n^4?#summation of series

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ASTOUNDING: 1 + 2 + 3 + 4 + 5 + ... = -1/12ASTOUNDING: 1 + 2 + 3 + 4 + 5 + ... = -1/12
Summation Formulas and Sigma Notation - CalculusSummation Formulas and Sigma Notation - Calculus
Prove That 1^4+2^4+3^4+⋯+𝑛^4= (𝑛(𝑛+1)(2𝑛+1) (3𝑛^2+3𝑛−1))/30Prove That 1^4+2^4+3^4+⋯+𝑛^4= (𝑛(𝑛+1)(2𝑛+1) (3𝑛^2+3𝑛−1))/30
Derivation | Formula | Sum of first n squares or square numbers 1^2 + 2^2 + 3^2 + 4^2 +...n^2Derivation | Formula | Sum of first n squares or square numbers 1^2 + 2^2 + 3^2 + 4^2 +...n^2
A Visual Attempt at 1 + 2 + 3 + 4 + 5 + ... = -1/12A Visual Attempt at 1 + 2 + 3 + 4 + 5 + ... = -1/12