If y = a cos(log x) + b sin(log x) Prove that x^2 yn+2 + (2n+1)x yn+1 + (n^2 + 1)yn =0 | In Tamil.

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π’š=𝒂𝒄𝒐𝒔(π’π’π’ˆπ’™)+π’ƒπ’”π’Šπ’(π’π’π’ˆπ’™) show that (x^2)yn+2+xyn+1(2n+1)+yn(n^2+)1 | | successive differentiationπ’š=𝒂𝒄𝒐𝒔(π’π’π’ˆπ’™)+π’ƒπ’”π’Šπ’(π’π’π’ˆπ’™) show that (x^2)yn+2+xyn+1(2n+1)+yn(n^2+)1 | | successive differentiation
If y=a cos(logx)+b sin(logx) ; prove that x^2yn+2 + (2n+1)xyn+1 + (n^2+1)yn=0||Using Leibnitz thm..If y=a cos(logx)+b sin(logx) ; prove that x^2yn+2 + (2n+1)xyn+1 + (n^2+1)yn=0||Using Leibnitz thm..
leibnitz,s theorem/y=acos(logx)+bsin(logx)leibnitz,s theorem/y=acos(logx)+bsin(logx)
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3. LEIBNITZ3. LEIBNITZ'S THEOREM | PROBLEM #2 | DIFFERENTIAL CALCULUS
y = acos(logx)+bsin(logx) then prove 1.) xΒ² y2+x y1+y = 0 2.) xΒ² y(n+2)+(2n+1)x y(n+1)+(nΒ²+1) yn=0y = acos(logx)+bsin(logx) then prove 1.) xΒ² y2+x y1+y = 0 2.) xΒ² y(n+2)+(2n+1)x y(n+1)+(nΒ²+1) yn=0