If cos θ +sin θ = m, sec θ + cosec θ = n then prove that n(m^2 - 1) = 2m Trigonometry Question

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If sin theta + cos theta = m and sec theta+ cosec theta = n, then prove that n(m^2-1) = 2mIf sin theta + cos theta = m and sec theta+ cosec theta = n, then prove that n(m^2-1) = 2m
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