Let a_1, a_2, a_3, … be in AP and a_p, a_q, a_r be in GP. Then a_q: a_p is equal to (a) r-p/q-p (...

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Let `a_1,a_2,a_3...` be in A.P. and `a_p,a_q,a_r` be in G.P. then value of `a_q/a_p` isLet `a_1,a_2,a_3...` be in A.P. and `a_p,a_q,a_r` be in G.P. then value of `a_q/a_p` is
Let a_1,a_2,a_3,… be terms of an A.P. If(a_1+a_2+⋯+a_p)/(a_1+a_2+⋯+a_q )=p^2/q^2 ,p≠q,thena_6/a_21.Let a_1,a_2,a_3,… be terms of an A.P. If(a_1+a_2+⋯+a_p)/(a_1+a_2+⋯+a_q )=p^2/q^2 ,p≠q,thena_6/a_21.
Let 𝑎_1,𝑎_2,𝑎_3….. be a G.P. of increasing positive terms. If a_1 a_5=28 and a_2+a_4=29, the a_6 isLet 𝑎_1,𝑎_2,𝑎_3….. be a G.P. of increasing positive terms. If a_1 a_5=28 and a_2+a_4=29, the a_6 is
Let a_1,a_2,a_3,… be in an A.P. such that ∑a_(2k-1) = (-72)/5 a_1 ,a_1≠0. If ∑a_k = 0, then n is:Let a_1,a_2,a_3,… be in an A.P. such that ∑a_(2k-1) = (-72)/5 a_1 ,a_1≠0. If ∑a_k = 0, then n is:
Let a1,a2,a3,..be a G.P. of increasing positive terms a1a5=28 a2|JEE Main paper|Session 1|2025|PYQsLet a1,a2,a3,..be a G.P. of increasing positive terms a1a5=28 a2|JEE Main paper|Session 1|2025|PYQs
P1 AP & GP Part 2 | Geometric Progressions (GP) | AS & A level Math 9709 | IGCSE/O-level Add MathP1 AP & GP Part 2 | Geometric Progressions (GP) | AS & A level Math 9709 | IGCSE/O-level Add Math
Let a1,a2,a3,__ be a GP of increasing positive terms. If a1a5=28 and a2+a4=29, then a6 is equal to:Let a1,a2,a3,__ be a GP of increasing positive terms. If a1a5=28 and a2+a4=29, then a6 is equal to: